dosbert2001's name

dosbert2001's name

PrimeSide

Member #687

September 2000

In a reply to the post 'ello' you said your name as Ben, but also said "I bet you can't guess how I got DYN though!". I know. You simply took the number of each letter in Ben (b = 2, e = 5, n = 14), squared that number (2 * 2 = 4, 5 * 5 = 25, 14 * 14 = 196), then wrapped any numbers that were over 26 around (ex. 27 = 1 = A) so that you got DYN (4 = D, 25 = Y, 196 wrapped around = 14 = N). Yay! I feel so proud now!

Shade

Member #1,152

April 2001

Seems like we have a mathwiz in our mids
I also have a little riddle:
try to make 24 by using the 4 numbers(1,3,4,6) only one time and at least one time.And also only using +,-,/,*,(,).
eg if you had to make 2 the solution could have been something like this:
((3*4)/6)*1.
To all mathwizards out there:LET THE GAMES BEGIN
Shade

Bruce Perry

Member #270

April 2000

It can be done, provided intermediate results are permitted to be quotients.

[censored - sorry, I feel guilty for cheating]

It is not possible if the result of a division is restricted to the set of all integers.

Hmm... can anyone prove this? (I can't, except by exhaustion )

[There, that's the new puzzle then. You won't be able to use a computer for this one.]

[ May 19, 2001: Message edited by: bdavis ]

--
Bruce "entheh" Perry [ Web site | DUMB | Set Up Us The Bomb !!! | Balls ]
Programming should be fun. That's why I hate C and C++.
The brxybrytl has you.

Shade

Member #1,152

April 2001

we seem to have a winner(that was fast )
congratulations bdavis,yes that is the only good solution.
I got the riddle of some mathematicians,they don't care about integer or real or whatever ,and furthermore those intermediate results are only a consequence of how you work it out=>
(6/(1-(3/4)))=(6/((4-3)/4)=(6*4)/(4-3)=24/1=24 =>you see only integer.
Anyone else who has some riddles???
Shade

Bruce Perry

Member #270

April 2000

I have to admit I did write a program to do an exhaustive search...

Here's one:

y = x^2 + x + 41, x E N (pseudo-notation; x is always a nonnegative integer)

Is y always a prime number?

(Anyone who uses a computer program to do this gets lynched...)

--
Bruce "entheh" Perry [ Web site | DUMB | Set Up Us The Bomb !!! | Balls ]
Programming should be fun. That's why I hate C and C++.
The brxybrytl has you.

Mars

Member #971

February 2001

If it would be true, there would be an infinitive amount of prime numbers.

But it is not yet proven whether there is an infinitve amount of prime numbers or not.

So it is not true.

--
This posting is a natural product. The slight variations in spelling and grammar enhance its individual character and beauty and in no way are to be considered flaws or defects.

Shade

Member #1,152

April 2001

bdavis:what you cheated!!!! that was a simple one,you should have solved it within an hour without a computer!!
About your riddle=> it can't,why?
the formula you give is a parabola wich would mean that all prime numbers from 41 and further should lie on it.Which isn't so.
(there also would be an infinite number of prime numbers ,and i heart a rumor somewhere that there aren't any more prime numbers beond 10^10^10^10^10^10 or so,just a rumor,i should ask one of the mathematicians)
Oh btw found a Y that isn't a prime=> if X=41 you get y=41^2 + 41 +41=41*43=>no prime
yes i got the jackpot
this was way to easy only 3m50sec to solve it
more plz(and no programming needed)
Shade

Araanor

Member #990

February 2001

The problem of the primes, The Riemann Hypothesis!

Shade

Member #1,152

April 2001

Araanor:and i thought the guy(Riemann) only was a pain because of his integrals.
new riddle what's the next number in the row:
10,11,12,13,14,15,16,17,20,22,24,31,100,121,???
Shade
(this might take a little longer unless you already know the answer )

Bruce Perry

Member #270

April 2000

Shade, take another look at my solution ::)

Yeah, that was an easy one. Sure is hard to come up with decent puzzles 8-)

Hmm, it wouldn't be 144, would it? (10*10=100, 11*11=121, 12*12=144) Somehow I doubt it though... ::)

--
Bruce "entheh" Perry [ Web site | DUMB | Set Up Us The Bomb !!! | Balls ]
Programming should be fun. That's why I hate C and C++.
The brxybrytl has you.

Ben Downey

Member #938

February 2001

Heh, I just found this post (been kinda busy lately).
I didn't think that anyone would actually care to figure that out!
PrimeSide did it exactly the way I did it. Good job!
I'm dumb!, you people have way too much time on your hands...

Shade

Member #1,152

April 2001

quote:Shade, take another look at my solution
quote: [censored - sorry, I feel guilty for cheating]
bdavis:hey man, you shouldn't feel sorry,you found a way to solve the problem,so why not use it
The answer to my new puzzle isn't 144(except if you could prove that 9^2=31 and 8^2=24...)
i'll give a few hints:

the number you have to find is the last one in the row ,there aren't any more numbers after that one.
16 (all the numbers have a conection to 16)

Try again i would say.
Anyone else
(Don't you worry i didn't find the answer myself. We got the riddle from one of our proffesors and after one hour only one of our class came up with the answer)
Shade

Bruce Perry

Member #270

April 2000

10000

W W! I can't believe I just got that :-)

10 (base 16) = 11 (base 15) = 12 (base 14) = ... = 31 (base 5) = 100 (base 4) = 121 (base 3) = 10000 (base 2)

(I didn't cheat BTW ::) )

--
Bruce "entheh" Perry [ Web site | DUMB | Set Up Us The Bomb !!! | Balls ]
Programming should be fun. That's why I hate C and C++.
The brxybrytl has you.

Shade

Member #1,152

April 2001

W W
that is the correct answer!!!!
congratulations,you are good at this!!
Shade

Goodbytes

Member #448

June 2000

Here's an easy one for you guys to solve:

Explain how the following equation works:

Chairman of Microsoft - 035 = evil

I thought I should add that this is not an anti-microsoft hate propaganda thing...

[ May 20, 2001: Message edited by: goodbytes ]

--
~Goodbytes

Gabhonga

Member #1,247

February 2001

hmm, I don't really have any clue regarding your riddle, goodbytes, but I know yet another riddle.
I've got this one from a pal of mine, who's got it from some book, I think, so this is an old one, but I particularly like it for its twists. that pal gave the riddle out to a round of 5 people, and I had been the only one who came up with the correct sollution, eheheh it took me 3 days or so
I particularly like it, because I've been able to puzzle the biggest math-freaks a lot with it, driving them into desperation, and I'm still waiting for the right sollutinon from some of them...so here it goes, and it's so damn easy....
given are the following 6 rows, each derived from its predecessor, but not the first, wich could be considered a "starting singularity".
the sollution questioned is the 7th row...
code:
1
11
21
1211
111221
312211

would be no wonder for me if some of you come out as baldheads on the other side, I had nearly ripped out all my dreads on this one...I hope you have fun!!! (btw, a 11 year old cousin of mine knew the sollution after 20 minutes...heheh)
~~gabhonga~~
[ May 20, 2001: Message edited by: 0xdeafbeef ]

--------------------------------------------------------
sigs suck

X-G

Member #856

December 2000

The next one is.. 13112221.
Solution? [removed. keep you busy. ]
[ May 20, 2001: Message edited by: X-G ]

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Since 2008-Jun-18, democracy in Sweden is dead. | 悪霊退散！悪霊退散！怨霊、物の怪、困った時は　ドーマン！セーマン！ドーマン！セーマン！　直ぐに呼びましょう陰陽師レッツゴー！

Gabhonga

Member #1,247

February 2001

correct...easy, isn't it? however most people tend to plug the most evil algorithms to that problem without looking at the first few lines...

--------------------------------------------------------
sigs suck

X-G

Member #856

December 2000

Oh, and here's another, easy one:
code:
[ 1][ 1][ 1][ 1]
[ 1][ 3][ 5][ 7]
[ 1][ 5][13][25]
[ 1][ 7][25][??]

lambik

Member #899

January 2001

Quote:

The next one is.. 13112221.

And the one after that 1113213211?

bill_mcniff

Member #1,105

March 2001

LAMBIK I THINK YOUR SIG IS SOME POOR EXCUSE FOR THIS QUOTE.
quote:Do not try to bend the spoon, that's impossible. Only try to realize that there is no spoon. Then you'll see it is not the spoon that bends, it is only yourself.
y0u PUNK ASS NEWBIE

Bruce Perry

Member #270

April 2000

X-G: 63. Heh, that was pretty easy 8-)

--
Bruce "entheh" Perry [ Web site | DUMB | Set Up Us The Bomb !!! | Balls ]
Programming should be fun. That's why I hate C and C++.
The brxybrytl has you.

lambik

Member #899

January 2001

Hi Bill,
quote:LAMBIK I THINK YOUR SIG IS SOME POOR EXCUSE FOR THIS QUOTE.
Yep, I watched the Matrix yesterday and couldn't help thinking of you when I saw that scene. Now I have to see it allover again to check that quote :-)
quote:y0u PUNK ASS NEWBIE
Oh oh, sorry to put you through an existential crisis.
I am Spoon. There is no Spoon. Therefore I am not?
Have a nice day Bill ;-)

Goodbytes

Member #448

June 2000

Well fine I'll tell you all the answer to my insanely difficult problem
quote:Explain how the following equation works:
Chairman of Microsoft - 035 = evil
The solution is so easy it's quite hilarious.
Add up the ASCII values for the string "BILL GATES", subtract 29(that's 035 in decimal) and you get 666. Come on, people that was easy!

--
~Goodbytes

X-G

Member #856

December 2000

And now, for a fiendishly clever (well, just insane, really) problem:

What number follows?

0010001011100000,
0000001101100100,
0000011101010110,
?

Hint: Think 4x4
[ May 21, 2001: Message edited by: X-G ]