In a reply to the post 'ello' you said your name as Ben, but also said "I bet you can't guess how I got DYN though!". I know. You simply took the number of each letter in Ben (b = 2, e = 5, n = 14), squared that number (2 * 2 = 4, 5 * 5 = 25, 14 * 14 = 196), then wrapped any numbers that were over 26 around (ex. 27 = 1 = A) so that you got DYN (4 = D, 25 = Y, 196 wrapped around = 14 = N). Yay! I feel so proud now!

Seems like we have a mathwiz in our mids
I also have a little riddle:
try to make 24 by using the 4 numbers(1,3,4,6) only one time and at least one time.And also only using +,-,/,*,(,).
eg if you had to make 2 the solution could have been something like this:
((3*4)/6)*1.
To all mathwizards out there:LET THE GAMES BEGIN
Shade

It can be done, provided intermediate results are permitted to be quotients.

[censored - sorry, I feel guilty for cheating]

It is not possible if the result of a division is restricted to the set of all integers.

Hmm... can anyone prove this? (I can't, except by exhaustion )

[There, that's the new puzzle then. You won't be able to use a computer for this one.]

[ May 19, 2001: Message edited by: bdavis ]

we seem to have a winner(that was fast )
congratulations bdavis,yes that is the only good solution.
I got the riddle of some mathematicians,they don't care about integer or real or whatever ,and furthermore those intermediate results are only a consequence of how you work it out=>
(6/(1-(3/4)))=(6/((4-3)/4)=(6*4)/(4-3)=24/1=24 =>you see only integer.
Anyone else who has some riddles???
Shade

I have to admit I did write a program to do an exhaustive search...

Here's one:

y = x^2 + x + 41, x E N (pseudo-notation; x is always a nonnegative integer)

Is y always a prime number?

(Anyone who uses a computer program to do this gets lynched...)

If it would be true, there would be an infinitive amount of prime numbers.

But it is not yet proven whether there is an infinitve amount of prime numbers or not.

So it is not true.

bdavis:what you cheated!!!! that was a simple one,you should have solved it within an hour without a computer!!
About your riddle=> it can't,why?
the formula you give is a parabola wich would mean that all prime numbers from 41 and further should lie on it.Which isn't so.
(there also would be an infinite number of prime numbers ,and i heart a rumor somewhere that there aren't any more prime numbers beond 10^10^10^10^10^10 or so,just a rumor,i should ask one of the mathematicians)
Oh btw found a Y that isn't a prime=> if X=41 you get y=41^2 + 41 +41=41*43=>no prime
yes i got the jackpot
this was way to easy only 3m50sec to solve it
more plz(and no programming needed)
Shade

The problem of the primes, The Riemann Hypothesis!

Araanor:and i thought the guy(Riemann) only was a pain because of his integrals.
new riddle what's the next number in the row:
10,11,12,13,14,15,16,17,20,22,24,31,100,121,???
Shade
(this might take a little longer unless you already know the answer )

Shade, take another look at my solution

Yeah, that was an easy one. Sure is hard to come up with decent puzzles

Hmm, it wouldn't be 144, would it? (10*10=100, 11*11=121, 12*12=144) Somehow I doubt it though...

Heh, I just found this post (been kinda busy lately).
I didn't think that anyone would actually care to figure that out!
PrimeSide did it exactly the way I did it. Good job!
I'm dumb!, you people have way too much time on your hands...

quote:Shade, take another look at my solution
quote: [censored - sorry, I feel guilty for cheating]
bdavis:hey man, you shouldn't feel sorry,you found a way to solve the problem,so why not use it
The answer to my new puzzle isn't 144(except if you could prove that 9^2=31 and 8^2=24...)
i'll give a few hints:

• the number you have to find is the last one in the row ,there aren't any more numbers after that one.

• 16 (all the numbers have a conection to 16)

Try again i would say.
Anyone else
(Don't you worry i didn't find the answer myself. We got the riddle from one of our proffesors and after one hour only one of our class came up with the answer)
Shade

10000

W W! I can't believe I just got that :-)

10 (base 16) = 11 (base 15) = 12 (base 14) = ... = 31 (base 5) = 100 (base 4) = 121 (base 3) = 10000 (base 2)

(I didn't cheat BTW )

W W
that is the correct answer!!!!
congratulations,you are good at this!!
Shade

Here's an easy one for you guys to solve:

Explain how the following equation works:

Chairman of Microsoft - 035 = evil

I thought I should add that this is not an anti-microsoft hate propaganda thing...

[ May 20, 2001: Message edited by: goodbytes ]

hmm, I don't really have any clue regarding your riddle, goodbytes, but I know yet another riddle.
I've got this one from a pal of mine, who's got it from some book, I think, so this is an old one, but I particularly like it for its twists. that pal gave the riddle out to a round of 5 people, and I had been the only one who came up with the correct sollution, eheheh it took me 3 days or so
I particularly like it, because I've been able to puzzle the biggest math-freaks a lot with it, driving them into desperation, and I'm still waiting for the right sollutinon from some of them...so here it goes, and it's so damn easy....
given are the following 6 rows, each derived from its predecessor, but not the first, wich could be considered a "starting singularity".
the sollution questioned is the 7th row...
code:
1
11
21
1211
111221
312211

would be no wonder for me if some of you come out as baldheads on the other side, I had nearly ripped out all my dreads on this one...I hope you have fun!!! (btw, a 11 year old cousin of mine knew the sollution after 20 minutes...heheh)
gabhonga
[ May 20, 2001: Message edited by: 0xdeafbeef ]

The next one is.. 13112221.
Solution? [removed. keep you busy. ]
[ May 20, 2001: Message edited by: X-G ]

correct...easy, isn't it? however most people tend to plug the most evil algorithms to that problem without looking at the first few lines...

Oh, and here's another, easy one:
code:
[ 1][ 1][ 1][ 1]
[ 1][ 3][ 5][ 7]
[ 1][ 5][13][25]
[ 1][ 7][25][??]

And the one after that 1113213211?

LAMBIK I THINK YOUR SIG IS SOME POOR EXCUSE FOR THIS QUOTE.
quote:Do not try to bend the spoon, that's impossible. Only try to realize that there is no spoon. Then you'll see it is not the spoon that bends, it is only yourself.
y0u PUNK ASS NEWBIE

X-G: 63. Heh, that was pretty easy

Hi Bill,
quote:LAMBIK I THINK YOUR SIG IS SOME POOR EXCUSE FOR THIS QUOTE.
Yep, I watched the Matrix yesterday and couldn't help thinking of you when I saw that scene. Now I have to see it allover again to check that quote :-)
quote:y0u PUNK ASS NEWBIE
Oh oh, sorry to put you through an existential crisis.
I am Spoon. There is no Spoon. Therefore I am not?
Have a nice day Bill ;-)

Well fine I'll tell you all the answer to my insanely difficult problem
quote:Explain how the following equation works:
Chairman of Microsoft - 035 = evil
The solution is so easy it's quite hilarious.
Add up the ASCII values for the string "BILL GATES", subtract 29(that's 035 in decimal) and you get 666. Come on, people that was easy!

And now, for a fiendishly clever (well, just insane, really) problem:

What number follows?

0010001011100000,
0000001101100100,
0000011101010110,
?

Hint: Think 4x4
[ May 21, 2001: Message edited by: X-G ]

W AH, that's s freaky! In maths club today, I offered that decreasing bases puzzle. They got it with a little (read: lots of) help from me... but then my teacher just came out with 1, 11, 21, ... - that exact same puzzle! I still didn't figure it out without help...
Anyway, here's a little program to churn them out... (my maths teacher thought, if anyone could do it, I could... )
code:
#include <conio.h>
#include <stdio.h>
char str1i[256] = "1";
char str2i[256];
char *str1 = str1i;
char *str2 = str2i;
int main() {
puts(str1);
while (getch() != 27) {
char *p1 = str1;
char *p2 = str2;
char n, c;
while (*p1) {
c = *p1;
n = 0;
while (*p1 == c) {n++; p1++;}
p2[0] = '0' + n;
p2[1] = c;
p2 += 2;
if (p2 - str2 >= 256) {puts("Too long."); return 0;}
}
*p2 = 0;
puts(str2);
(int)str1 ^= (int)str2;
(int)str2 ^= (int)str1;
(int)str1 ^= (int)str2;
}
return 0;
}
Anyway, they thought my puzzle was too hard. Someone offered this puzzle. See if you can get it...
1, 2, 6, ?
This is a set of only four numbers. What is the last number?

Someone like me?

Let p1,p2,p3,...,pn be the first n prime numbers (p1=2,p2=3,p3=5,...).

q = p1*p2*p3*...*pn

q is therefore divisible by all the prime numbers up to pn. So q + 1 divided by any prime number up to pn gives a remainder of 1, so q + 1 is prime.

Therefore, given a set of all prime numbers up to a particular size, there will always be another prime number that's greater.

Hence there are an infinite number of primes.

Man, I feel so stupid when someone goes into math theory mode like that. I understand it, but I couldn't have come up with it to save my miserable life.

I found this cool website with a nice free engine. with similar to C style code its called VERGE maybe some of you have heard of it VERGE ENGINE WEBSITE
The page also has some quality *FINISHED* RPGs. Nice engine I might make a game with it. after I finish with this one

bdavis:
let's see
1,2,6,??
that could be 24(row of x!)
that could be 42(next=previous + sqr(previous)
hell i don't know.
quote: quote:
--------------------------------------------------------------------------------
(there also would be an infinite number of prime numbers ,and i heart a rumor somewhere that there aren't any more prime numbers beond 10^10^10^10^10^10 or so,just a rumor,i should ask one of the mathematicians)
--------------------------------------------------------------------------------
Someone like me?
no i meant someone of the mathematicians in my class who went to all courses of philosophy and still remember
greetz
Shade

Umm... 16? (two previous numbers times two.. of course, this assumes the non-existant number before 1 is zero)

Those solutions are all very well, but they don't explain why the number you have to find is the only other number in the set.

Any more suggestions?

Clue: a kid could do this

23yrold3yrold: Don't worry, I didn't come up with that. I just quoted it

Hmm, I like this big grin

This is still about 1,2,6...? Ok, I'll give it a shot. I'd say 12, and here's why:
if we divide each number in the series by it's current position (starting at 1), we get:
1/1,2/2,6/3,... = 1,1,2,...
Looks like Fibonacci to me. So of course, then next one is 3, times its position, which is 4. So that's 12.
(edit: spelling)
[ May 22, 2001: Message edited by: Bob ]

Nope. How can you be sure that's the last number in the set?

Hehe, I seem to have you all baffled. And this is S simple! You must think in the way you thought when you were THREE (*wink* wink, that has a triple meaning )

[ May 22, 2001: Message edited by: bdavis ]

Ooh! ooh! Is it 10? One has three letters, two is the next to have three letters, then six, and lastly ten.

Hey! I get it! The last number is 3!

Well, PrimeSide seems to have it figured out, so here's a new puzzle that I made up(I feel so special that I made it up )
What is the next number in the series?
51
27
11
This one is really tough(it took me a while to figure out after I invented it ), so I'll give you a cryptic hint or two:
- You have to convert these numbers to a different base.
- Make sure to split the converted numbers into two small bites.

Congratulations, PrimeSlide!
So the three meanings were:
1. Think like a kid;
2. The words are three letters long;
3. I wrote 'THREE' rather than '3' to suggest writing numbers out.
I had no idea the threefoldness of the meanings would incite Goodbytes to guess 3. I really feel like Commander Data now, with all these conspicuous references to the number 3...

bdavis: H3y! I was only joking!!!!!3 ;3

Heh, I would never have guessed that one.
1 Een
2 Twee
6 Zes
10 Tien

goodbytes:
Blind guess: 5 ?
Since a "bite" is likely a "nibble", which is half a byte, I converted it into binary. Appears the HO nibble was shifting its bits to the right. After decimal 11, which is binary 00001011 (HO nibble rsh:ed all the way), we try shifting the LO nibble, which turns to binary 101 = decimal 5.
edit: typo
[ May 23, 2001: Message edited by: X-G ]

and another one...
Ones upon a time there was a city ,surrounded by a big wall and with only one gate.To enter this city you have to tell the guard the secret number.So to find out what the secret number is you hide yourself in the bushes and listen to what the people and the guard say:
G:5
P1:4
when the next person arives
G:7
P2:5
and the next
G:11
P3:6
and now it's your turn
G:12
YOU:???

and for those of you who can thing multidimensional:How many ribs has a 4-dimensional cube(3D has 12 ribs(ribs=lines between the points of the object,i'm not sure what the actual translation is))?

shade

X-G:nemo custudiet ipsos custudes.
i just couldn't resist
Shade

Lucky guess: 7?

Nope,it's not seven.
(i forgot to say the people who come at the gate don't know anything about the previous person)
Try again
Shade

Hmm...
Shade: we just call them 'edges'
Let E(n) be the number of edges and V(n) be the number of vertices in an n-dimensional cube.
For n >= 2, we take two (n-1)D hypercubes and connect each vertex in one to the corresponding vertex in the other to create the nD hypercube.
V(n) = 2 V(n-1)
E(n) = 2 E(n-1) + V(n-1)
For n = 1, we have a line connecting two vertices. Thus we can form the sequence:
V(1) = 2, E(1) = 1
V(2) = 4, E(2) = 4
V(3) = 8, E(3) = 12 (as expected for a cube)
V(4) = 16, E(4) = 32
Thus a 4D hypercube has 32 edges.

thx bdavis,i was also concidering the word verticles(but that would have been really wrong)
anyone else who wants/has multidimensional riddles??
Shade(i really should be studying my astronomy )

X-G: Nope
You were right with the nybbles(it's spelled with a y though I think). You have to convert the numbers into binary, and then separate them into nybbles. The rest should be easy...

Shade, you're into astronomy? Then I have a question (not a puzzle, a question ):

I have a game where the stars are placed as in real life; all the constellations are there. However, I seriously doubt that my stopgap solution has placed the stars at their correct distances.

So either:

1. Do you know of a downloadable star catalogue containing the distance of each star, or:

2. Do you know of one with sufficient information to work it out, and how would I do this?

Thanks

[ May 23, 2001: Message edited by: bdavis ]

Goodbytes: it seems it's optional; you can have 'nibble' or 'nybble' www.dictionary.com/cgi-bin/dict.pl?term=nybble

Shade:

Answer is 8, yes? To get in the gate?

Heh... I prefer nybble. It looks cooler

bdavis:stop gabsolution???
me into astronomy??just because i have to,it's a course i have to follow at univ...
let's see how might i be able to help you??
I don't know any star catalogues,but i probably could find one,and with wathever information they give i'll probably be able to figure out the distance...
Do you need this really quick??or could you wait till ,let's say 27 june?(that's my last exam after that i will have plenty of time to help you out,just send me a msg or mail by then so i don't forget)ok?
23Yrold3yrold: nope it's not eight either
try again.(and this one is so simple)
Shade

My stopgap solution has a certain amount of science involved. I look at the spectral class of the star (just a single letter), and I guess a temperature from the spectral class. Then I guess the star's brightness (and this really is a guess ), and apply inverse-square law against the star's observed magnitude to estimate the distance. Last time I checked, the closest star to the sun was 1.7 light-years away (should be 4.3, for Alpha Centauri - I don't even know if it was the right star, and it probably wasn't).

Microsith Planet Exploder (the project with these stars in) has to be ready by the last day of term - I'm pretty sure it's early July. Maybe I'd better ask around on some newsgroups... Thanks anyway

I hope it works
when the game is finished ,are you going to put it on this site??i really would like to see it.
if there are problems with the formulas(eg problem with dimensions and stuff,don't be afraid to ask,astromomers have the nasty habbit of using different units for the same dimension(length->parsec,lightyear,astronomical units(AU),meter...)it sometimes is really confussing))
anyways GOOD LUCK
noone seems to get through the gate
Shade
sorry for the inconveniance of the message
(and my probably confussing & bad english)

Well I don't want to make a fus about your confussing bad English

Yep, MSPE will be uploaded here. BTW it's inspired by www.microsith.com. I've even got permission from the webmaster

Shade: I can't believe no one got this one yet...

The answer to the puzzle is 5. When the guard tells you a number, you reply with the number of letters in that number's name.

Bdavis:
goodbytes:your theory is fine,but you probably wouldn't get in either.
12=TWELVE --->6
12=DOUZE --->5=>but because there are more ppl here who know some English i have to go for the English version.
(french part of Canada??)
Shade

Shade: Umm... well did I get it or not? And if the city were in Canada, the conversation would go like this:
G: Twelve. Douze.
YOU: Six. Cinq.
G: You may enter the city. Vous pouviez entrez la ville.
(On leaving)
G: Did you like your stay in town? Avez-vous aimez votre visite en ville?
YOU: No. To many bilingualists. Non. Trop de bilingues.

I hate bilingualists. Je déteste des bilingualists.
Don't you hate bilingualists? Ne détestez-vous pas des bilingualists?
But even worse than bilingualists are trilingualists. Mais encore plus mauvais que des bilingualists sont les trilingualists.
And the worst of all are people that know more than three languages. Et de tous les plus mauvais sont les gens qui savent plus de trois langages. Y el peores de todos son la gente que sabe más de tres lenguajes. Und allen falschsten von sind Leute, die mehr als drei Sprachen kennen. Ed il più difettosi di tutti sono la gente che conosce più di tre linguaggi. E de todos o mais maus são os povos que sabem mais de três línguas. そしてすべての最も悪いの人々である3 つ以上の言語を知ってい
る。 그리고 모두의 가장 나쁜 것 사개 이상 언어를 아는 사람 이다
. 并且最坏全部是知道超过三种语言的人们。

-But of course, English is my native language

Eh bien, a moins que la grammaire française canadienne n'est comme celle de l'anglais américain , soit le gardien ne sait rien, la conversation irait plus comme ça :
VOUS: Vous pouvez entrer dans la ville.
GARDIEN: Avez-vous aimé votre séjour en ville?
VOUS: Non. Trop de bilingues.
J'ai tort sans doute aussi...
CageCode : il n'existe pas le mot 'bilingualist', ni en anglais ni en français. En anglais c'est 'bilingual' (oui, c'est un nom; 'bilinguist' n'existe pas). En français c'est 'bilingue'.
Il faut dire : << Je déteste les bilingues >> et << ... sont ceux qui savent plus de trois langues >>
Hmmm... did you use an automatic translator?
Not that I'm pedantic or anything
[ May 25, 2001: Message edited by: bdavis ]

Il Um, approvazione, in modo da il mio francese non è tutto che grande - ma hey, conosca tedesco, spagnolo, Portugese, l' italiano, il francese, il cinese, il giapponese, il Russo ed il Coreano, PIÙ circa 20 linguaggi di programmazione differenti, in modo da prenderlo facile, giusto?

ok ok ok goodbytes you get in
You are very lucky if people are that kind of bilingual.Here in Belgium in Brussels it should be the same ,but it isn't(they would only know the French and not the Dutch )
The dialog would be something like this
G(only knows French) ouze
Y(refusing to speak French):vijf
G:????ne comprend pas.
Y(still refusing but now also showing the correct amount of fingers(this is so wrong)):vijf
G a little bit angered):qq tu dit?!Je ne comprend pas.
Y(seeing it won't help ,just try in your best French):cinq.
G(quite aggitated let's you in without saying a word ,only looking very pissed at you).
when you have entered the city you hear him talk to an other guard and you only hear some of what they say:
G1:...quel idiot...sais pas francais...
G2:...C'est vrai...tous ces idiot...
G1:...nous...Neerlandais?...whahaha
Shade
Could those multilinguists please stop,my head hurts.
A tous ces multilinguists,taisez vous svp.Mon tête fait du mal.
Kunnen die meertaligen nu effekes stil zijn .Ik heb koppijn.
Ceteri censeo cartaginem esse delendem,ac ipsos custodes de X-G te occident.(just kidding)
Könten die ...(i'm going to stop here my head hurts)

ok ok, come back from talking foreign languages to that language which we all love: maths

So did goodbytes get the answer Shade? Did we have to be bilingual to get it, or is there another way?

Yes An Ly gootbytes got the answer.he just has a little counting problem,probably tired or something(no offence)
ok here's a new one(very simple this time)
I V X L
Shade

An Ly: look at the beginning of Shade's last post. You don't have to be multilingual.
Shade: I thought Belgium was a French-speaking country "Ma tête me fait mal."
Anyway, back to maths:
There are seven tetrominoes (tetris pieces).code:# # # # ## # ##

1. ## ## # # ## ##

2. # # ## # #

#Is it possible to fit them into a 4x7 block without gaps or overlap? Prove your answer.

C? Roman numerals...

Funny... I thought Shade was just being stupid. This is the first time I noticed that I mistakenly wrote that twelve has five letters in it... wow that's really embarassing. Must... cover up... temporary lack... of coolness... ... ahh, that's better.

Heh wow I feel retarded now... but seriously doesn't 12 seem like it has 5 letters? It still does to me

Oh and bdavis, just to let you know, they're called "tetrads"(I had a good laugh out of this when learning about meiosis in biology class )

bdavis: All you have to do is rip the tetrads apart, feed them through a food-processing machine or wood chipper, and then pour them into a 4x7 inch pan, and bake for 15-20 minutes at 475 degrees. Mix lemon and icing sugar in small bowl and lightly glaze.

WHAT BELGIUM FRENCH SPEAKING!!!!
- did you think my french would contain mistakes if it were my native language???
ok let me explain:
In Belgium there are 3 official languages
-Dutch(also called Flamish)
-French
-German
In Flanders(where i live)we speak Dutch,that are only something like 6000000 ppl
In "La Wallonie" they speak French(or something like that),that is something like 4000000 ppl
Brussels=> lets just cal that a nightmare,it sould be bilingual but for official intsances that most of the times means French only.
And German is what is spoken in the'Oost kantons'(that's just a minority)
The first half of the century there have been a lot of problems in flanders because then Duch wasn't considdered an official language(although 5M ppl spoke it),there have been some riots most known is May '68.
In the beginning of the century all univerities and higher education in flanders was in french,luckyly that has changed,and it's all in Dutch now.(and something that might sound strange is that the germans in WWII have done a great deal for the flamish ppl)
... no more about that.But please never forget that french isn't the only language in Belgium.
C is the answer,roman numerics
gootbytes:i know i first thought i had misspelled 12 myself but the dictionary helpt me out=>i was right.
Shade

Calm down Shade! Aren't we touchy today? Hehe... BTW I said it was Roman numerals...

Goodbytes: you're right: a 'tetrad' (when not related to biology or atomic structure) is apparently a group or set of four. I just called them 'Tetrominoes' because that's what they were called when I first saw the puzzle.

BTW I forgot to mention the pieces cannot be in any way dismantled, destroyed, minced, folded, splatted or otherwise antidisestablishmentariated.

Any clues? (No, I shall not accept 'exhaustive search' as a proof.)

auch now you got me
(and i should know that,i have to do exam of that course in 10 days=> need to study)
note though that the kelvin scale is entirely experimental,so those constants can be chosen to fit,i should find out.1 thing i kinda like remember is that it's just coincidence that 1K=1°C.
(THermodynamics aren't that easy)
Quote from the professor that gave Thermo(about the sciences):
if it's living it's Biologie.
if it stinks t's chemistry.
if it does not work than it's physics.
Shade(me master? bwahaha tel my professors
)

Actually I've heard both Tetrominoes and Tetrads used, for what it's worth...And haven't we done this whole "lets show off wieviele Sprache wir kennen" thing in another thread already...?

Shade: interesting. We got a very similar quote from a chemistry teacher a couple of years ago.
If it's dead, it's biology.
If it smells, it's chemistry.
If it doesn't work, it's physics.

Biology is watching videos and colouring in.
Chemistry is cooking.
Physics is getting five results and saying it's proven.
Maths is the only true ... truth. (Sorry, my eloquence seems to have gone today )
Wasn't the F/C/K (insert appropriate vowel ) argument in another thread?

Oh, and have you ever noticed - if you go to France, or Germany, or anywhere else for that matter, the dogs always bark in English, the cats always mew in English, the birds always chirp in English...?

Woeps,looks like something went wrong with my previous post,wrong thread.

sorry for the inconvenience.

the puzzle with the tetrispieces will probably be impossible

shade

Can you prove it? You'll be so cheesed off when I tell you the answer...

bdavis: I think it's impossible... you need to replace one of the
code:
00
00

pieces with a
code:
000
0

for it to work.
Don't ask me why, of course I'm wrong
Edit: fixed Tetrad formatting
[ May 27, 2001: Message edited by: goodbytes ]

OK, no-one seems to be able to prove it. Here we go:
The 4x7 block you need to fill should be shaded in a hatching pattern:code:0101010
1010101
0101010
1010101There are 14 '1's and 14 '0's.
Then we can deduce how the pieces will lie in the grid:code:0 0 1 01 0 01
1 10 10 1 1 10
0 1 0 0 01
1In any of these, the '0's and '1's may be swapped. Either way they all cover two '0's and two '1's. Thus the final piece must cover two '0's and two '1's.
The final piece will look like this:code:0 1
10 or 01
0 1It cannot cover two '0's and two '1's.
Hence the puzzle is impossible.

a dog barking in "german": "Wuff!", or: "Wau!"
a cat mewing: "Miau!" or "Mau!" or even "Maunz!"
a pig: "Oink, Oink!!"
a cow: "MuuUUUuh!"
a gabhonga: "GNAaa!!"
...

GRRRRRR HAUGHYARGHFUIGHYURRAHGK!!!!

a sheep: B-A-A-A-A-A-A-A-A-A-A-A-A

ok,considering we are talking about animals now:does anybody know how to make a cat bark like a dog??

shade

Is this a reference to Pinkie(sp?) and the Brain?

I wouldn't know?(don't think so)
it has something to do with petrol and matches.
shade

Pinky (or Pinkie - not sure) and the Brain is a children's cartoon. Every episode, the two eponymous mice try to take over the world. Brain does all the work, and Pinky[ie] just acts stupid. In one episode, Brain had a potion that gave dog instincts to whoever swallowed it. He gave it to a cat to stop the cat from trying to eat them.

No? I don't know the answer then

Shade: Yup - set it on fire. Whoof!
Incidentally, how does one make a dog sound like a cat?

X-G:simple use a chainsaw MIAAAUW
(this really is cruel isn't it)
btw i'm just happy to see you
(where did you get that )
Shade

Hey... nobody diss Pinky & the Brain, it's the coolest

Just something I found floating around.. I'll try and change my motto every week

Goodbytes: agreed Not that I like all children's programmes

BTW does anyone remember Knightmare? I wish they'd bring that back

P.S. Click the smilies...

http://bdavis.netfirms.com/tubbydie.gif

[ May 29, 2001: Message edited by: bdavis ]

X-G:I was just wondering because i heard something in the same style by "Geert Hoste"(Belgian comedian):
"Is that a gun in your pocket or are you just happy to see me?"(was in a joke about how the pollice would control people to check for the illegal use of viagra)
I prefer Tom&Jerry cartoons
Shade

Of course, no children's series will ever match up to The Super Mario Bros. Show(with The Legend Of Zelda every friday)

The "Is that a (insert noun here) in your pocket or are you just happy to see me?" is a classic phrase, mutated a thousand times.

Ok new riddle:
there is an army consisting out 6Legions with each of them 6 officers of a different rank(so each legion has 1 A officer,1 B officer...)
now is the question ,place those 36 officers in a 6x6 square and in each row and collumn there may only be one officer of each legion and one officer of each rank.
let's see if anyone can solve this one
shade

Damnit!

That's a tricky one, Shade. Got some work to do, if I can't solve it today I'll write a program to tear it apart MUAHAHAHA!

yes i know it's a tricky one and programming help is allowed.:evilgrin:
go for it people.
shade
[ May 31, 2001: Message edited by: Shade ]

I heard about this puzzle in Maths Club (don't worry, I don't already know the answer ). Apparently it only works for certain grid sizes - 4, 6, 8 and 10, or something like that. I know it doesn't work for 2 (in fact it's damn obvious), and I don't think it works for odd numbers...

[ May 31, 2001: Message edited by: bdavis ]

It was a foodnote in my cursus of algebra.
(and if it's possible has nothing to do with beeing odd or not)
You really wil hate me when i tell you the answer.
good luck with it.
(but if i were you i would ask some help from some other geniouses that hang around here somewhere)
shade

bdavis:it works for some odd values
eg 3
=> 1,2,3 & A,B,C
code:
1A 2B 3C
2C 3A 1B
3B 1C 2A

keep trying
shade

Yeah, I realised that after I posted that message I was just trying to suck up by saying I'd heard of the problem