error C2440: '=' : cannot convert from 'std::string' to 'void *'

code:

string name;
peer -> data = name;

So... how to make this work ?
I basically have to convert string to void and void to string afterwards...
tried "peer -> data = &name;" but that adds letters and numbers before the actual string...

and the definition of peer: (part of it)

typedef struct _ENetPeer
{ ...
...
void * data;
...

and I CANT modify the definition of peer.

Any help is appreciated !

The compiler throws this error because you are trying to compare an object with a pointer. If you really want to, you can change the string like this:
std::string* name;
But I don't get why you would want to change it to a void pointer.

/edit:
I was using the wrong words(compare instead of assign) and I didn't fully read his post. nvm

http://en.wikipedia.org/wiki/Type_conversion

It should work: http://en.wikipedia.org/wiki/Type_conversion#Explicit_type_conversion_in_C-like_languages

peer->data = (void*)name.c_str();
cout << "Peer->data: " << (char*)peer->data << endl;

Well that's strange, because that should work just fine as well (first version with the &name).

What do you mean by "was not giving me anything"? If you mean trying to display the data field as a C-string afterwards revealed nothing then I understand.

Consider the following example:

void *data = NULL;
string name("Dennis");
data = reinterpret_cast<void*>(&name);

This compiles and runs just fine. But outputting data as a C string won't work, because all it holds is the address of the name string, which is a C++ datatype and not just a pointer to a zero terminated string, so it contains other data before the actual character data. I've checked in my environment during debug and the first memory byte at the address of name was 0 (which in case of interpreting the data at that address as a zero terminated C "string" (not to confuse with the string type from C++) explains why trying to display that reveals nothing).