Here is the link again.

Going down the list line by line:

1 through 5 are adjustable. You can manually change or drag the points around.

1. p1 is player position
2. p2 is bullet position
3. A is angle player is traveling (relative to the line p1 to p2 not the x axis)
4. v1 is player speed
5. v2 is bullet speed

make an imaginary triangle
6. j is horizontal distance p2 to p1
7. k is vertical distance p2 to p1
8. l is absolute distance p2 to p1

9. F is angle from x axis to the line p2 to p1

10 I meant to remove (it is duplicated at line 18)

11. calculate B - using the similar triangle method I described earlier (law of sines)
12. calculate C
13. calculate c of smaller similar triangle where a = pv and b = bv and using C (law of cosines)
14. calculate time t based of the two similar c's, where l is c from big triangle

Next 2 lines 15 and 16 I calculate collision point using both A and B
(A + F) is absolute angle to x axis of player to collision
(180 - B + F) is absolute angle to x axis of bullet to collision
I have 90 + 90 - (B - F) so I could visualize it in my head while I was doing it. Starting at 90 how much to add 90 - (B - F).

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15. calculate point p3 = player + time * speed * angle
16. calculate point p4 = bullet + time * speed * angle

this part of that is where we get bv.x and bv.y
bv.x = bv * cos(180 - B + F)
bv.y = bv * sin(180 - B + F)

p4.x = bullet.x + time * bv.x
p4.y = bullet.y + time * bv.y

17, 18 and 19 are lines drawn between the points with limits put in

2 triangles.

The "big" triangle has 3 sides.

Side a is a vector where start is player and end is collision
Length a = time * player speed

Side b is a vector where start is bullet and end is also collision.
Length b = time * bullet speed

Side c is a vector where start is player and end is bullet

We don't know time so we can't calculate a or b. We can calculate c with distance formula.

"Small" triangle is a similar triangle where all sides lengths are divided by time
a = player speed
b = bullet speed
c = unknown

In my example I used trig to calculate small c. Then take ratio of big c to little c to calculate time.