Answers in this post are>>

    int score = 656;
    char scorestring[50];
    snprintf(scorestring, sizeof(scorestring), "%d", score);
    int scorelength = strlen(scorestring);
    for (scoredigit = 0; scoredigit < scorelength; scoredigit++)
    {
    textprintf_ex(activepage, font, 0 + (scoredigit * 17), 0, makecol(255, 255, 255), -1, "%i", scorestring[((scorelength - 1) - scoredigit)] - 48);
    }

also replacing the snprintf(scorestring, sizeof(scorestring), "%d", score); with

    itoa(score, scorestring, 10);

will do the same thing. But it is considered non standard.

Original question.
I am using a new numbering system in my game where as before I just put the text on the screen. What I can not figure out is how to.

1. Find out how many places my score uses. I.E. If score was 1423 it would be 4 places

2. How to take just 1 number from the score. I.E. 1423 is the score and I wanted just the 3rd number I would have 4.

I used to have an old program in Qb that a Binary number and made it decimal. Dont know how acurate it was but it did what I am looking for or close to it.

DIM BinNum(1 TO 300) AS STRING, NStringNum(1 TO 300) AS LONG
CLS
INPUT "Binary String:_ ", BinNum$
FOR LoopStart = 1 TO LEN(BinNum$)
 BinNum$(LoopStart) = MID$(BinNum$, LoopStart, 1)
 NStringNum(LoopStart) = VAL(BinNum$(LoopStart))
NEXT
FOR LoopStart = 1 TO LEN(BinNum$)
 DecimalNum = DecimalNum + NStringNum(LoopStart) * (2 ^ (LEN(BinNum$) - LoopStart))
NEXT
PRINT DecimalNum

other then the example I don't know what it is called if even pointed in the correct direction I could do a little research on it. But I never really learned more then the basics of C/C++ and when straight into allegro.

For positive numbers:

int digit_count = (int)log10(num) + 1;

int digit_value = (int)(num / pow(10, place)) % 10;

Thanks that was what was needed

digit_count = (int)log10(score) + 1;

digit_value = (int)(score / pow(10, 1)) % 10;

textprintf_ex(active_page, font, 0, 0, makecol(255, 255,  255), -1, 
"Digits in score %i Digit Value %i", digit_count, digit_value);

Only thing is if score is 0 digit_count returns a large negitive number but that is easy to get around with a simple check if the number is not positive just post a 0 score.

Thanks a lot.

Well at the very beginning of the game the score is going to be 0 so that value will be returned until the score is >0

Finished Result:

digit_count = (int)log10(score + totalscore) + 1;
    for (scoredigit = 0; digit_count > scoredigit; scoredigit++)
    {
        draw_sprite(active_page, numbers[(int)((score + totalscore) / pow(10, scoredigit)) % 10], 275 - scoredigit *17, 15);
    }
    digit_count = (int)log10(lives) + 1;
    if ((int)log10(lives) + 1 < 0)
        draw_sprite(active_page, numbers[0], 275, 15);
    for (livesdigit = 0; (int)log10(lives) + 1 > livesdigit; livesdigit++)
    {
        draw_sprite(active_page, numbers[(int)(lives / pow(10, livesdigit)) % 10], 100 - livesdigit *17, 15);
    }

I have one last problem with this though if score + totalscore = 1000 it passes 0000 and if score + totalscore = 2000 it passes 1000 till 10000 it passes 19000 for some reason the 4th digit doesn't display properly until the score = 1001 and so on. I don't see where the problem is any one else?

Some where in here is the problem I just can't seem to isolate it.

digit_count = (int)log10(score + totalscore) + 1;
    for (scoredigit = 0; digit_count > scoredigit; scoredigit++)
    {
        draw_sprite(active_page, numbers[(int)((score + totalscore) / pow(10, scoredigit)) % 10], 275 - scoredigit *17, 15);
    }

Edit: wow i type slow 3 post came out of nowhere
Edit2: i think my way is better because you can get ohold of the 1st 2nd and nth numbers

Edit3:

i think your bug lie in the (int) casting

Hey Circle , this might help.

Until I decide to write my own function to convert integers into strings , I've been using Itoa

Link to usage at cplusplus.com
http://www.cplusplus.com/reference/clibrary/cstdlib/itoa.html

Example

Then if you wanted to convert the digit you found from numberstring use
atoi (in stdlib.h) to change it back to an integer.

Hope this was helpful.

I suggest you use snprintf() instead of itoa(). itoa() is non-standard. Plus, you get some extra memory safety you wouldn't get otherwise.

[EDIT]

You're transforming the digit into ASCII, then transforming it into an integer, and then printing it (which will, again, transform it into ASCII). Just print it as a char instead.
textprintf_ex(screen, font, SCREEN_W/2 - (4*19) - scoredigit * 30, SCREEN_H/2, makecol(255,255,255), -1, "%c", scorestring[(score_length - 1) - scoredigit]);

And might I suggest you stop draw directly to the screen? Use a buffer of some kind.

You can have an allegro font and replace the digit bitmaps in that font with your own digit bitmaps. That would save you the hassle of rewriting the functionality (well, too late now ), but it may also be faster.

Nooo!! My whole world just collapsed...

You've missed a parameter there.

Replace the first two lines with:

snprintf(livestring, sizeof(livestring), "%d", score + totalscore);
snprintf(mousehstring, sizeof(mousehstring), "&d", mouseh);

The first parameter of snprintf() is the character array (string) you're writing to, the second parameter is the maximum number of characters to write (though, it will actually copy this ammount minus one characters, since it appends a null terminator). From there after, you write a format specifier, and supply additional variables, as you would to any of the printf() variants.

Because it was 2am, and I'd been drinking for a couple of hours. They should of course both be %d, as you figured out.

Same as above.

There was no &mouseh in my example. The line I wrote should have just given you a warning about having too many format arguments.