i use c language.
i have one array of string and one char variable and i want to compare they value is same or not ,so wat should i do .
math_q1 is the question arrays.
The math_a1 store the answers of the question example 2 + 3 =
the multiple choice is 1 : 7, 2 : 6, 3 : 5 the 4 th row store the right answers position.

get the key input 1 or 2 or 3 from user
compare the value key in with the 4 th row of array;
char *math_q1 [5] = {"2 + 3 = ","6 + 7 = ","2 + 8 = ","7 + 10 = ","9 + 12 = "}
char *math_a1 [4][5] = {
{"7","15","8","17","21"},
{"6","14","10","15","22"},
{"5","13","13","13","23"},
{"3","3","2","1","1"}
}
char answers = ureadkey(NULL);
if(answers == math_a1[4][1])
{......}
but problem is answers is char and math_al is array of string
i am doing a quiz game ,is this good way to do this ?

I really didn't understand what you want to do... but in any case Fladimir's tip should do it
BTW:

Considering you're changing your sig very instensely, I guess OpenLayer 2.0 is just getting the last hits on the anvil?

Then use strcmp instead of the == operator to test the equality of strings. If you want to get really fancy you could also ignore case and strip the trailing and leading spaces from the input etc.

Maybe I'll just have to solve a color issue with the framebuffers (probably caused by the way that AllegroGL uploads the textures) and a few other things.

The best way would be to use a real GUI. But if you want to do it by yourself here's a quick article about it.

You're reading only one key, not a string. But as you have predefined choises to choose from, that's enough. To convert a char to a string you could use the age old trick:

char *answer[2];
answer[0] = ureadkey(NULL);
answer[1] = '\0';

// Or if you want you could also use sprintf:
sprintf( answer, "%c", ureadkey( NULL ));