ALLEGRO_COLOR in array

ALLEGRO_COLOR in array

lCoopsl

Member #16,804

February 2018

I'm experiencing a strange issue of ALLEGRO_COLOR definitions having their values disappear when initialized in an array. It seems like it has something to do with function scope.

#SelectExpand
  1ALLEGRO_COLOR test[1] = {
  2    al_map_rgb(50,50,50),
  3};
  4
  5int main(int argc, char **argv) {
  6
  7    //Allegro initialization snip
  8
  9    std::cout << test[0].r << std::endl;
 10
 11    return 0;
 12}

cout returns '0'.

However,

#SelectExpand
  1int main(int argc, char **argv) {
  2
  3    //Allegro initialization snip
  4
  5    ALLEGRO_COLOR test[1] = {
  6        al_map_rgb(50,50,50),
  7    };
  8
  9    std::cout << test[0].r << std::endl;
 10
 11    return 0;
 12}

Properly returns the float value.

Any ideas whats happening here?

Elias

Member #358

May 2000

You cannot use al_map_rgb (or any other Allegro functions) before you call al_init.

--
"Either help out or stop whining" - Evert

Edgar Reynaldo

Major Reynaldo

May 2007

The problem is not initialization in an array, rather it is because of initialization before al_init is called.

ALLEGRO_COLOR mycol() {
   return al_map_rgb(255,196,127);
}

int main(int argc , char** argv) {
   if (!al_init()) {return 0;}
   ALLEGRO_COLOR c = mycol();/// works fine

   return 0;
}

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lCoopsl

Member #16,804

February 2018

Thanks for the response, sometimes its simpler than you think I guess.