Triforce Programming Challenge

Kibiz0r

My internet friend had an interesting assignment for his programming midterm, so I thought I'd share it with you guys and see how creative we can get with our solutions.

Use whatever language you like; cookies for participants.

The Problem

Assume the user gives you a numeric input ranging from 1 to 7.

When the input is 1, print the following:

***********
 *********
  *******
   *****
    ***
     *

Values greater than one should generate multiples of the pattern, ending with the one above, but always stacked symmetrically.

For example, 3 should print the following:

*********** *********** ***********
 *********   *********   ********* 
  *******     *******     *******  
   *****       *****       *****   
    ***         ***         ***    
     *           *           *     
      *********** ***********
       *********   ********* 
        *******     *******  
         *****       *****   
          ***         ***    
           *           *     
            ***********
             ********* 
              *******  
               *****   
                ***    
                 *

For bonus points, also print the reverse:

*********** *********** ***********
 *********   *********   ********* 
  *******     *******     *******  
   *****       *****       *****   
    ***         ***         ***    
     *           *           *     
      *********** ***********
       *********   ********* 
        *******     *******  
         *****       *****   
          ***         ***    
           *           *     
            ***********
             ********* 
              *******  
               *****   
                ***    
                 *     
                 *     
                ***    
               *****   
              *******  
             ********* 
            ***********
           *           *     
          ***         ***    
         *****       *****   
        *******     *******  
       *********   ********* 
      *********** ***********
     *           *           *     
    ***         ***         ***    
   *****       *****       *****   
  *******     *******     *******  
 *********   *********   ********* 
*********** *********** ***********

My Solution

I used C#. I wrote the tests first, as I do with most programming tasks, especially those with detailed data manipulation. The first pass was completely imperative, with a ton of loops and counters all shoving stuff into a buffer, but once I had something working I boiled it down to its essence and LINQified it.

Source code below.

Program.cs#SelectExpand
  1using System;
  2using System.Collections.Generic;
  3using System.Linq;
  4using System.Text;
  5
  6namespace ConsoleApplication1
  7{
  8    class Program
  9    {
 10        static void Main(string[] args)
 11        {
 12            Console.WriteLine("Welcome, Hero of Time");
 13            Console.WriteLine("How many triforces?");
 14            var iterations = Int32.Parse(Console.ReadLine());
 15            Console.WriteLine("Do you want to reverse them as well?");
 16            var reverse = Boolean.Parse(Console.ReadLine());
 17            Console.WriteLine(Triforce.MakeTriforce(iterations, reverse));
 18            Console.ReadKey(true);
 19        }
 20    }
 21}

Triforce.cs#SelectExpand
  1using System;
  2using System.Collections.Generic;
  3using System.Linq;
  4using System.Text;
  5
  6namespace ConsoleApplication1
  7{
  public static class Triforce
  {
      private static IEnumerable<string> makeTriforceIteration(int buffer, int iteration)
      {
          var triforce = @"***********
********* 
*******  
 *****   
  ***    
   *     ";
          var bufferString = String.Join("", Enumerable.Repeat("      ", buffer));
          return from line in triforce.Split(new string[] { Environment.NewLine }, StringSplitOptions.None)
                 select bufferString + String.Join(" ", Enumerable.Repeat(line, iteration));
      }
 22
      public static string MakeTriforce(int iterations, bool reverse)
      {
          var result = (from buffer in Enumerable.Range(0, iterations)
                       let iteration = iterations - buffer
                       select makeTriforceIteration(buffer, iteration)).SelectMany(s => s);
          if (reverse)
          {
              result = result.Concat(result.Reverse());
          }
          return String.Join(Environment.NewLine, result);
      }
  }
 35}

TriforceTest.cs#SelectExpand
   1using System;
   2using System.Collections.Generic;
   3using System.Linq;
   4using System.Text;
   5using NUnit.Framework;
   6
   7namespace ConsoleApplication1
   8{
  [TestFixture]
  public class TriforceTest
  {
      [Test]
      public void ProducesASingleTriforceWhenInputIs1()
      {
          var singleTriforce = @"***********
********* 
*******  
 *****   
  ***    
   *     ";
          Assert.That(Triforce.MakeTriforce(1, false), Is.EqualTo(singleTriforce));
      }
  23
      [Test]
      public void ProducesTwoTrifocesWhenInputIs2()
      {
          var doubleTriforce = @"*********** ***********
*********   ********* 
*******     *******  
 *****       *****   
  ***         ***    
   *           *     
    ***********
     ********* 
      *******  
       *****   
        ***    
         *     ";
          Assert.That(Triforce.MakeTriforce(2, false), Is.EqualTo(doubleTriforce));
      }
  41
      [Test]
      public void ProducesThreeTrifocesWhenInputIs3()
      {
          var tripleTriforce = @"*********** *********** ***********
*********   *********   ********* 
*******     *******     *******  
 *****       *****       *****   
  ***         ***         ***    
   *           *           *     
    *********** ***********
     *********   ********* 
      *******     *******  
       *****       *****   
        ***         ***    
         *           *     
          ***********
           ********* 
            *******  
             *****   
              ***    
               *     ";
          Assert.That(Triforce.MakeTriforce(3, false), Is.EqualTo(tripleTriforce));
      }
  65
      [Test]
      public void ProducesReverse()
      {
          var reverseTriforce = @"*********** *********** ***********
*********   *********   ********* 
*******     *******     *******  
 *****       *****       *****   
  ***         ***         ***    
   *           *           *     
    *********** ***********
     *********   ********* 
      *******     *******  
       *****       *****   
        ***         ***    
         *           *     
          ***********
           ********* 
            *******  
             *****   
              ***    
               *     
               *     
              ***    
             *****   
            *******  
           ********* 
          ***********
         *           *     
        ***         ***    
       *****       *****   
      *******     *******  
     *********   ********* 
    *********** ***********
   *           *           *     
  ***         ***         ***    
 *****       *****       *****   
*******     *******     *******  
*********   *********   ********* 
 104*********** *********** ***********";
          Assert.That(Triforce.MakeTriforce(3, true), Is.EqualTo(reverseTriforce));
      }
  }
 108}

Matthew Leverton

#SelectExpand
  1<?php
($t = $argc > 1 ? intval($argv[1]) : 3) > 0 or die("enter count > 0\n");
($A = $argc > 2 ? intval($argv[2]) | 1 : 11) > 0 or die("enter size > 0\n");
$B = ($A + 1) / 2;
  5
ob_start();
do
{
  for ($z = 0; $z < $B; ++$z)
  {
    echo str_repeat(' ', $s);
    for ($y = 0; $y < $t; ++$y) echo str_repeat(' ', $z).str_repeat('*', $A-($z*2)).str_repeat(' ', $z+1);
    echo "\n";
  }
  $s += $B;
}
while (--$t);
echo rtrim($b = ob_get_clean());
 19
foreach (array_reverse(explode("\n", $b)) as $l) echo "$l\n";
 21?>

Edit: added second parameter.

./triforce.php [count [size]]

ImLeftFooted

Nice.

trap15

Wrote this one in C, my usual choice for everything. Thought of using python, but meh.
Does the inverse one as well

#SelectExpand
  1#include <stdio.h>
  2
  3void print_chunk(char string[], int count, int starts)
  4{
      int i;
      for(i = 0; i < starts; i++)
              printf("      ");
      for(i = 0; i < count; i++)
              printf("%s", string);
      printf("\n");
 11}
 12
 13void print_triforce_strip(int count, int start, int dir)
 14{
      if(dir == 0) {
              print_chunk("*********** ", count, start);
              print_chunk(" *********  ", count, start);
              print_chunk("  *******   ", count, start);
              print_chunk("   *****    ", count, start);
              print_chunk("    ***     ", count, start);
              print_chunk("     *      ", count, start);
      }else{
              print_chunk("     *      ", count, start);
              print_chunk("    ***     ", count, start);
              print_chunk("   *****    ", count, start);
              print_chunk("  *******   ", count, start);
              print_chunk(" *********  ", count, start);
              print_chunk("*********** ", count, start);
      }
 30}
      
 32int main(int argc, char *argv[])
 33{
      int i;
      int c = atoi(argv[1]);
      for(i = 0; i < c; i++) {
              print_triforce_strip(c - i, i, 0);
      }                      
      for(i = 0; i < c; i++) {
              print_triforce_strip(i + 1, c - i - 1, 1);
      }
      return 0;
 43}

Matthew Leverton

I like this version better:

#SelectExpand
  1<?php
  2  ($t = $argc > 1 ? intval($argv[1]) : 3) > 0 or die("enter count > 0\n");
  3  ($A = $argc > 2 ? intval($argv[2]) | 1 : 11) > 0 or die("enter size > 0\n");
  4  $B = ($A + 1) / 2;
  5
  6  for ($j = 0, $b = ''; $j < $t; ++$j)
  7  {
  8    $l = str_repeat(' ',$j * $B).str_repeat(' '.str_repeat('*', $A), $t-$j). ' ';
  9    for ($i = 0; $i < $B; ++$i, $l = strtr($l, array(" *"=>"  ", "* *" => "   ", "* "=>"  ")))
 10      $b .= "$l\n";
 11  }
 12
 13  echo rtrim($b).implode("\n", array_reverse(explode("\n", $b)))."\n";
 14?>

trap15

Anyone gonna make a 1-liner Perl script to do it? :-X

kazzmir

Mine is in python and uses combinators. Not the shortest..

#SelectExpand
   1#!/usr/bin/env python
   2
   3def reverse(l):
   4    return l[::-1]
   5
   6class Triangle:
   7    def __init__(self, height = 7):
   8        self.height = height
   9
  10    def lines(self, pixel = '*'):
  11        for length in range(self.height - 1, 0, -1):
  12            yield ' ' * (self.height - length - 1) + pixel * (length * 2 - 1) + ' ' * (self.height - length)
  13
  14class Printer:
  15    def __init__(self, triangle):
  16        self.triangle = triangle
  17
  18    def show(self):
  19        for line in self.triangle.lines():
  20            yield line
  21
  22class CombinePrinter(Printer):
  23    def __init__(self, p1, p2):
  24        self.p1 = p1
  25        self.p2 = p2
  26
  27    def show(self):
  28        s1 = self.p1.show()
  29        s2 = self.p2.show()
  30        while True:
  31            try:
  32                yield s1.next() + s2.next()
  33            except StopIteration:
  34                break
  35
  36class SequencePrinter(Printer):
  37    def __init__(self, printer1, printer2):
  38        self.printer1 = printer1
  39        self.printer2 = printer2
  40
  41    def show(self):
  42        s1 = self.printer1.show()
  43        s2 = self.printer2.show()
  44        while True:
  45            try:
  46                yield s1.next()
  47            except StopIteration:
  48                break
  49        while True:
  50            try:
  51                yield s2.next()
  52            except StopIteration:
  53                break
  54
  55class SpacePrinter(Printer):
  56    def __init__(self, printer, space):
  57        self.printer = printer
  58        self.space = space
  59
  60    def show(self):
  61        s1 = self.printer.show()
  62        while True:
  63            try:
  64                yield " " * self.space + s1.next()
  65                # yield s1.next()
  66            except StopIteration:
  67                break
  68
  69class ReversePrinter(Printer):
  70    def __init__(self, printer):
  71        self.printer = printer
  72
  73    def show(self):
  74        out = reverse([line for line in self.printer.show()])
  75        for line in out:
  76            yield line
  77
  78def printN(num):
  79    all = [Printer(Triangle()) for x in xrange(0, num)]
  80    return reduce(lambda a, b: CombinePrinter(a, b), all)
  81
  82def triforce(height):
  83    all = [SpacePrinter(printN(total), (height - total - 1) * 6) for total in xrange(1, height)]
  84    return reduce(lambda a, b: SequencePrinter(b, a), all)
  85
  86def printit(printer):
  87    for line in printer.show():
  88        print line
  89
  90# Printer().show(Triangle())
  91# printit(CombinePrinter(CombinePrinter(Printer(Triangle()), Printer(Triangle())), Printer(Triangle())))
  92# printit(printN(5))
  93# printit(SequencePrinter(printN(5), SpacePrinter(printN(4), 6)))
  94def doit(n):
  95    printit(SequencePrinter(triforce(n), ReversePrinter(triforce(n))))
  96
  97import sys
  98doit(int(sys.argv[1]))

Xuzzers

New user here.

My four-line solution in Python 2 (or 3?), doesn't do the reverse:

def triforce(num):
  for i in range(num - 1, -1, -1):
    for x in range(5, -1, -1):
      print (' ' * (6 * (num - 1 - i))) + ' '.join(('%s%s%s' % (' ' * (5 - x), '*' * ((2 * x) + 1), ' ' * (5 - x)) for m in range(0, i + 1)))
      
triforce(int(input()))

Not sure how to do the fancy code tags, but that works, I guess .

Edit: fixed.

Kibiz0r

The bar has been raised!

This is my most compact solution, using a string extension for String.Repeat().
Edit: Removed prompts.

#SelectExpand
  1using System;
  2using System.Linq;
  3
  4namespace ConsoleApplication1
  5{
  6    class Program
  7    {
  8        static void Main(string[] args)
  9        {
 10            var iterations = Int32.Parse(Console.ReadLine());
 11            var reverse = Boolean.Parse(Console.ReadLine());
 12            var triforce = from i in Enumerable.Range(0, iterations)
 13                           from j in Enumerable.Range(0, 6)
 14                           select " ".Repeat(6 * i) + (" ".Repeat(j) + "*".Repeat(11 - j * 2) + " ".Repeat(j + 1)).Repeat(iterations - i);
 15            Console.WriteLine(reverse ? String.Join(Environment.NewLine, triforce.Concat(triforce.Reverse())) : String.Join(Environment.NewLine, triforce));
 16        }
 17    }
 18}

Xuzzers

Now, what does that say about Python and C# ;P.

Kibiz0r

They both let you take the long way or the short way?

Thomas Fjellstrom

n/m

Dustin Howett

Perl one-liner, does not do reverse. Takes a single argument on the commandline.

#SelectExpand
 1map { print "".(" " x (6*int($_/6))), ((" " x ($_%6)).("*" x (11-2*($_%6))).(" " x ($_%6))." ") x ($ARGV[0]-int($_/6)), "\n"; } ((0 .. (6*$ARGV[0])-1));

(EDIT: The following prints it reversed as well.

#SelectExpand
 1map { print "".(" " x (6*int($_/6))), ((" " x ($_%6)).("*" x (11-2*($_%6))).(" " x ($_%6))." ") x ($ARGV[0]-int($_/6)), "\n"; } ((0 .. (6*$ARGV[0])-1), reverse(0 .. ((6*$ARGV[0])-1)));

)

Can be run as:

/usr/bin/perl -e 'map { print "".(" " x (6*int($_/6))), ((" " x ($_%6)).("*" x (11-2*($_%6))).(" " x ($_%6))." ") x ($ARGV[0]-int($_/6)), "\n"; } ((0 .. (6*$ARGV[0])-1));' 3

Peter Wang

... What?

#SelectExpand
  1#include <stdio.h>
  2#include <stdlib.h>
  3
  4char *tri[] = {
  5"***********",
  6" ********* ",
  7"  *******  ",
  8"   *****   ",
  9"    ***    ",
 10"     *     "};
 11
 12int main(int argc, char *argv[])
 13{
 14    int h = atoi(argv[1]);
 15    int x, y, w;
 16    for (w = h; w > 0; w--) {
 17        for (y = 0; y < 6; y++) {
 18            for (x = 0; x < (h - w) * 6; x++)
 19                putchar(' ');
 20            for (x = 0; x < w - 1; x++)
 21                printf("%s ", tri[y]);
 22            printf("%s\n", tri[y]);
 23        }
 24    }
 25    for (w = 1; w <= h; w++) {
 26        for (y = 5; y >= 0; y--) {
 27            for (x = 0; x < (h - w) * 6; x++)
 28                putchar(' ');
 29            for (x = 0; x < w - 1; x++)
 30                printf("%s ", tri[y]);
 31            printf("%s\n", tri[y]);
 32        }
 33    }
 34    return 0;
 35}

Kibiz0r

Xuzzers said:

Now, what does that say about Python and C# ;P.

Modded my solution to look slightly more like yours*, just because it looks eerily similar for two languages you probably wouldn't place next to each other at the dinner table.

*Looks almost exactly the same if you run it through a C# interpreter to avoid the boilerplate stuff!

I'll try a Ruby solution tomorrow if I feel like it.

ImLeftFooted

Obligatory whitespace solution.

(Only 7 lines)

Peter Wang

Haskell:

#SelectExpand
  1go n = do
  2  mapM putStr $ map unlines $ reverse $ map reverse $ rows n
  3  mapM putStr $ map unlines $ rows n
  4
  5rows n = [padrow (n-i) (row i) | i <- [1..n]]
  6
  7padrow w = map (sp ++)
  8  where sp = replicate (6*w) ' '
  9
 10row 1 = tri
 11row n = zipWith join tri (row (n-1))
 12
 13join x y = x ++ " " ++ y
 14
 15tri = map line [1..6]
 16
 17line n = sp ++ replicate (n*2-1) '*' ++ sp
 18  where sp = replicate (6-n) ' '

axilmar

c++:

#SelectExpand
  1#include <iostream>
  2using namespace std;
  3
  4int main() {
  cout << "input triforce number: ";
  int n;
  cin >> n;
  for(int t = n; t > 0; --t) {
      for(int i = 11; i >= 1; i -= 2) {
          for(int j = 0; j < (n-t)*12/2; ++j) cout << " ";
          for(int k = 0; k < t; ++k) {
              for(int j = 0; j < 11/2 - i/2; ++j) cout << " ";
              for(int j = 0; j < i         ; ++j) cout << "*";
              for(int j = 0; j < 12/2 - i/2; ++j) cout << " ";
          }
          cout << endl;
      }
  }
  return 0;
 20}

Xuzzers

One line of Python:

print('\n'.join('\n'.join(((' ' * (6 * n)) + ' '.join(('%s%s%s' % (' ' * (5 - x), '*' * ((2 * x) + 1), ' ' * (5 - x)) for m in range(i + 1)))) for x in range(5, -1, -1)) for n, i in enumerate(range(int(input()) - 1, -1, -1))))

Doesn't print the reverse, at least yet ::)

Edit: Online! The stuff with input() is to fake it when there is no input() allowed. http://codepad.org/ZwE4KsP3

ImLeftFooted

#SelectExpand
  1#include <iostream>
  2using namespace std;
  3
  4int main() {
  cout << "input triforce number: ";
  int n;
  cin >> n;
  for(int t = n; t > 0; --t) {
      for(int i = 11; i >= 1; i -= 2) {
          cout << string((n-t)*12/2, ' ');
          for(int k = 0; k < t; ++k) {
              cout << string(11/2 - i/2, ' ');
              cout << string(i,          '*');
              cout << string(12/2 - i/2, ' ');
          }
          cout << endl;
      }
  }
 19}

X-G

All I keep thinking is newfags can't triforce.

axilmar

#SelectExpand
  1#include <iostream>
  2#include <string>
  3using namespace std;
  4
  5template <class T> T repeat(int times, const T &t) { return times > 0 ? t + repeat(times - 1, t) : T(); }
  6
  7int main() {
  8    cout << "input triforce number: ";
  9    int n;
 10    cin >> n;
 11    for(int t = n; t > 0; --t) {
 12        for(int i = 11; i >= 1; i -= 2) {
 13            cout << string((n-t)*6, ' ') << repeat(t, string(5 - i/2, ' ')+string(i,'*')+string(6 - i/2, ' ')) << "\n";
 14        }
 15    }
 16}

Arthur Kalliokoski

Quote:

newfags can't triforce [knowyourmeme.com].

Well, truth be told, I seen the original post about 1 hour after it started, and began working on a plain old C implementation. About 15 minutes after that, I saw the "Now, what does that say about Python and C#" quote, and was somewhat flummoxed. Anyway, during the course of this I was informed that I no longer had a job, which torqued my gourd for quite a few hours, so I gave up entirely. But in the end, there have been a few posts well beyond what I'm capable of, so kudos to you . Other subjects and areas of interest notwithstanding of course...

LennyLen

Arthur Kalliokoski said:

I seen the original post

You what?

Sirocco

Load "triforce",8,1
Run

Arthur Kalliokoski

Quote:

I seen the original post

I first saw the original post?

Kibiz0r

Concurrent version lolol:

#SelectExpand
  1using System;
  2using System.Linq;
  3
  4namespace ConsoleApplication1
  5{
  6    class Program
  7    {
  8        static void Main(string[] args)
  9        {
 10            var iterations = Int32.Parse(Console.ReadLine());
 11            var reverse = Boolean.Parse(Console.ReadLine());
 12            var triforce = from i in ParallelEnumerable.Range(0, iterations)
 13                           from j in ParallelEnumerable.Range(0, 6)
 14                           select " ".Repeat(6 * i) + (" ".Repeat(j) + "*".Repeat(11 - j * 2) + " ".Repeat(j + 1)).Repeat(iterations - i);
 15            Console.WriteLine(reverse ? String.Join(Environment.NewLine, triforce.Concat(triforce.Reverse())) : String.Join(Environment.NewLine, triforce));
 16        }
 17    }
 18}

1000 iterations (and reverse)
Single-threaded: 1.175s
Multi-threaded: 0.669s

bamccaig

Kibiz0r said:

var iterations = Int32.Parse(Console.ReadLine());
var reverse = Boolean.Parse(Console.ReadLine());

That's just ugly. :-/ It would be easier to use args. >:( Both Parse methods are going to throw if the line isn't parse-able anyway so if you were going for compact you could just ignore an args.Length check and get similar behavior for incorrect usage.

Bruce Perry

triforce :- triforce(3).
triforce(N) :- triforce(N,6).
triforce(N,Size) :- triforce(N,Size,true).
triforce(N,Size,Reverse) :- triforce(N,Size,Reverse,0).
triforce(N,Size,Reverse,Indent) :- N>0, triforce(N,Size,Reverse,Indent,0).
triforce(0,_Size,_Reverse,_Indent).
triforce(N,Size,Reverse,Indent,Row) :-
  Row<Size, Off is 1+Row*2, On is Size*2-Off, Indent2 is Indent+1, Row2 is Row+1,
  tfScan(N,Indent,On,Off), triforce(N,Size,Reverse,Indent2,Row2), (Reverse, tfScan(N,Indent,On,Off); true).
triforce(N,Size,Reverse,Indent,Size) :- N2 is N-1, triforce(N2,Size,Reverse,Indent).
tfScan(N,Indent,On,Off) :- N>0, tfRun(' ',Indent), tfRun('*',On), N2 is N-1, tfScan(N2,Off,On,Off).
tfScan(0,_Indent,_On,_Off) :- nl.
tfRun(C,M) :- M>0, write(C), M2 is M-1, tfRun(C,M2).
tfRun(_C,0).

Can be invoked with a query such as

?- triforce.
?- triforce(3).
?- triforce(3,6).
?- triforce(3,6,true).

where the 3 is the number of triangles, the 6 is the size of each one, and the Boolean is whether to print the reverse Triforce.

Neil Black

X-G said:

All I keep thinking is newfags can't triforce

▲
▲ ▲

Bruce Perry

My program briefly output
▲
▲ ▲
at one stage during its development. Much hilarity ensued.

Kibiz0r

X-G said:

All I keep thinking is newfags can't triforce

My Facebook after posting my solution said:

Newfags can't from i in Enumerable.Range(0, iterations) from j in Enumerable.Range(0, 6) select repeat(" ", 6 * i) + repeat(repeat(" ", j) + repeat("*", 11 - j * 2) + repeat(" ", j + 1), iterations - i);

Neil Black

Kibiz0r said:

You win. I'm not sure what you win, but you definitely win.

BAF

Did you seriously write that in Prolog?

Bruce Perry

Yes

And what's more, a female friend got me into it

Arthur Kalliokoski

http://stackoverflow.com/questions/2406780/code-golf-triforce

Kibiz0r

Oh wow.

bamccaig

Oh no, the Interwebs! Hide!

Martin Kalbfuß

A bit late, but the compiler had a bug, which is fixed now.

The Modula-2 version:

#SelectExpand
  1MODULE triforce;
  2
  3FROM STextIO IMPORT WriteChar, WriteString, WriteLn;
  4FROM SWholeIO IMPORT ReadCard;
  5
  6VAR n : CARDINAL;
  7
  8PROCEDURE DrawTriforce(cur, max : CARDINAL);
  9VAR i1, i2, i3 : CARDINAL;
 10BEGIN
 11     IF cur > max THEN RETURN END;
 12     FOR i1 := 0 TO 5 DO
 13         FOR i2 := 0 TO cur * 6 DO WriteChar(' ') END;
 14         FOR i2 := 0 TO max - cur DO 
 15              FOR i3 := 1 TO i1 DO WriteChar(' ') END;
 16              FOR i3 := 1 TO (11 - i1 * 2) DO WriteChar('*') END;
 17              FOR i3 := 0 TO i1 DO WriteChar(' ') END;
 18         END;
 19         WriteLn(); 
 20     END;
 21     DrawTriforce(cur + 1, max);
 22END DrawTriforce;
 23
 24BEGIN
 25     WriteString('Amount: ');
 26     ReadCard(n);
 27     DrawTriforce(0, n - 1);
 28END triforce.

machine

Just saw this challenge, not planning on doing it in full yet, but the simplest way I find to generate a triangle is to think of it as a square, and then increasingly "sculpt" out the edges.

int end = 11; int begin = 0;
for(int i = 0; i < 6; i++) { /*six rows*/
for(int k = 0; k < begin; k++) { std::cout << " "; }
for(int j = 0; j < end; j++) { std::cout << "*"; } std::cout << "\n"; end -= 2; begin++;
}

Kibiz0r

Well, this is pretty much done. Good job, everybody!

Thread #603383. Printed from Allegro.cc