Hi

first of all, sorry for my bad English. I try my best^^.

i wont to write a very simple code, that could calculate a physic variable with a function.

this is the simplest version of the code:

int fall(int *h) {
int g = 9;
int t = 10;

if (h > 0) {
*h = (g / 2 * (t * t));
}
}

this is a very simple kind to calculate it!! but first i wont to try if its work trough given consts and after it I will change the code so, that it could calculate the time and the high by itself

but its very simple, thers a picture wich should fall down, but if i run the code, the ball is on the ground.
i think i need timer or extra operators for the movement, which reduce the fps. But i think everybody who worked with graphics movement, know what i mean.

int fall(int &h) {
int g = 9;
int t = 10;

if (h > 0) {
h *= (g / 2 * (t * t));
}
}

or

int fall(int &h) {
int g = 9;
int t = 10;

if (h > 0) {
h = h*(g / 2 * (t * t));
}
}

no this istn what i mean

look this is the code

if i start it
the picture is imediatly at the ground, whithout that i can see how its falls

My god man, learn to use indentation!

The problems (well, besides the complete lack of indentation) are twofold:
1) is that you don't time your code. Read the FAQ.
2) t starts at 10, making h start at 450, which, depending on the graphics mode you've set, may be outside the screen.

Oh, and I know capitalization exists in German, so please use it in English as well.

Ok Ok sorry, but Im in stress here.

Ok i try it.
And if i get a problem, I will knew whom I have to ask ^^

I think it'd be 500, since he's using ints. Or is it 400? I can never remember if integer division rounds up or down.

@Max S: Timer logic will help maintain the proper speed on varying computers. You also need to understand the logic of a game loop. You only need to do a portion of your "fall" function each loop. You can add a float value to multiply the final calculation to make it only do 10% of the calculation per game loop. There are methods, I'm just rambling about some food-for-thoughts.

At the beginn I sad that this is just a simple version of the code.
When it's done, the funktion calculate the h und how long it needs to fall, by it self.

But first i will try to make this counter work, this is the harder part for me.

Doesn't round at all. It just chops the decimal part off. So 400.

You guys and your technical accuracy. Bah, VB6.0 I believe did some form of rounding and I just carried the concept.